A force of 12 N is exerted on a box. The component of this force which acts along the ground has a magnitude of 9.19 N, as shown below.
What is the measure of angle x?
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OpenStudy (anonymous):
OpenStudy (anonymous):
a) 40°
b)26.8°
c) 30°
d) 37.4°
OpenStudy (anonymous):
have you studied trigonometry ?
OpenStudy (anonymous):
nope
OpenStudy (anonymous):
im in geometry right now
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OpenStudy (anonymous):
ooo...
i think this will be solved by trigonometry
cos0 = adjacent/hypotenuse
0=theta
adjacent is the side which is the nearest to the angle but not the longest
hypotenuse is the longest side of the triangle
since
cos 0 = adjacent/hypotenuse
0 = cos-1 (9.19/12)
OpenStudy (anonymous):
how would you get degrees?
OpenStudy (anonymous):
the solution should be in degrees
OpenStudy (anonymous):
because in physics you are pretending (in a diagramm) that the relation between the two forces (12 N and 9.19 N) is equal on the drawing.
OpenStudy (anonymous):
apart your calculator is set to radian meassure
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
a?
OpenStudy (anonymous):
a? don't understand
OpenStudy (anonymous):
a) 40°
OpenStudy (anonymous):
is that right?
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OpenStudy (anonymous):
40.01881388739993 right
OpenStudy (anonymous):
12cos(x) = 9.19
cos(x) = 9.19/12
x = 40 degrees
OpenStudy (anonymous):
i think that's right
OpenStudy (anonymous):
but the equation must be \[\cos^{-1} (9.19/12)\]
OpenStudy (anonymous):
iam not sure if you are doing the right conversion