Question

Write the equation of the line that is parallel to the line 4x − 3y = −12 and passes through the point (−3, 4).

Answer 1

Answer Choices:
y = 4/3x + 8

y = 4/3x + 3

y = −3/4x + 8

y = −3/4x + 3

Answer 2

change the original equation so that you get the gradient
4x - 3y = -12
-3y = -12 -4x
y = 4 + 4/3x
so the gradient is 4/3
the second equation will become
y = 4/3x + c
now to find c, substitute the coordinates into the equation
4 = -12/3 + c
4 = -4 + c
c = 8
so the equation should be
y = 4/3x +8

Answer 3

Can you help me with one more.?

Answer 4

yes

Answer 5

Write the equation of the line that is perpendicular to the line 2x − 3y = 3 and passes through the point (−8, 2).

Answer 6

this question is very similiar to the previous one
change the equation such that we can get the gradient
-3y = -2x +3
y = 2/3x -1
so the gradient is 2/3
well in this case for perpendicular lines, the product of the gradient is -1.
divide -1 by 2/3 and we get -3/2
the equation we get will be
y = -3/2x + c
to find c, substitute the coordinates into the equation
2 = 24/2 + c
2 = 12 + c
c = -10
so the equation is
y = -3/2x -10

Answer 7

Thank you so much (: