Question

A fireworks company has two types of rockets called
Zinger 1 and Zinger 2. The polynomial -16t2+150t gives the
height in feet of Zinger 1 at t seconds after
launch. The polynomial: -16t2 + 165t gives the
height of Zinger 2 at t seconds after launch. If
the rockets are launched at the same time and both
explode 6 seconds after launch, how much higher is
Zinger 2 than Zinger 1 when they explode? Explain your answer to me so I could understand.

Answer 1

A. 414 ft

B. 990 ft

C. 90 ft

D. 324 ft

Answer 2

#4. Plug t = 6 into the two formulas.
Zinger 1: -16 * t^2 + 150 * t = -16 * 6^2 + 150 * 6 =
Zinger 2: -16 * t^2 + 165 * t = -16 * 6^2 + 165 * 6 =

Answer 3

okay 414 ?

Answer 4

did u calculate it

Answer 5

yes I got that tho ... I had used that formula but i dnt know if my answer is right.

Answer 6

wait let me calculate

Answer 7

never mind check this one distance that Z1 travels = -16(6)^2+150(6)
distance that Z2 travels = -16(6)^2 + 165(6)
distance between them = -16(6)^2 + 165(6) - (-16(6)^2+150(6)) = 90

Answer 8

I'm i right

Answer 9

414 is correct

Answer 10

are you sure I did it again... distance that Z1 travels = -16(6)^2+150(6)
distance that Z2 travels = -16(6)^2 + 165(6)
distance between them = -16(6)^2 + 165(6) - (-16(6)^2+150(6)) = 90

Answer 11

Substituting the value t = 6 in the first equation gives:
(-16 * 36) + (165 * 6) = -576 + 990 = 414

Answer 12

this is what the first polynomial gives

Answer 13

ohhh okay so then my work was wrong...okay then I get it ...

Answer 14

thank you again..

Answer 15

Ur welcome