A company's monthly profit, P, from a product is given by P = -x2 + 105x - 1050, where x is the price of the product in dollars. What is the lowest price of the product, in dollars, that gives a monthly profit of $1,550? (Do not put a $ in your answer.)

Question

jackellyn · Answer

1500= -x^2 +105x -1050
-x^2 +105x -1050-1500
-x^2 +105x -2550

do the quadratic formula
a=-1
b=105
c=-2550

can you?

tennistar · Answer

no

tennistar · Answer

@rebeccaskell94

tennistar · Answer

plz help me understand

accessdenied · Answer

Essentially, we want to find the smallest value of $x$ that makes our monthly profit $P = 1550$.
  To do this, we may let $P = 1550$.  Then, we plug in the equivalent expression of $P$ in terms of $x$ given by the problem ($P = -x^2 + 105x - 1050$).

So our equation is:
  $-x^2 + 105x -1050 = 1550$

Does that part make sense?

tennistar · Answer

yeah, I got the answer, with a little help thanks

accessdenied · Answer

Ah, okay.  You're welcome.

What answer did you get, just checking?