Question

Calculate the limit (post
)

Answer 1

\[\lim_{x \rightarrow -\infty}\sqrt{4x^2+1}{-1}/{x}\]

Answer 2

\[ \lim_{x \rightarrow 0^+} \sqrt{4x+1}{-1}/{x}\]

Answer 3

\[
\lim_{ x\to 0^+} \frac{\sqrt{4x+1}-1}{x}=\\

\lim_{ x\to 0^+} \frac{\sqrt{4x+1}-1}{x}\frac{\sqrt{4x+1}+1}{\sqrt{4x+1}+1}=\\

\lim_{ x\to 0^+} \frac{ 4x+1 -1}{x}\frac{1}{\sqrt{4x+1}+1}=\\
\lim_{ x\to 0^+}4\frac{1}{\sqrt{4x+1}+1}=4\frac{1}{2}=2\\

\]

Answer 4

Do you have any questions?

Answer 5

u already solve the second question

Answer 6

those 2 are different problem

Answer 7

Good. Do the first one like this one.

Answer 8

i see how u get the second problem @eliassaab

Answer 9

going to get the opp result

Answer 10

Let me know what you will get.

Answer 11

4 for the first one