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An antiderivative of 3x^2/(2x^3-5) is:
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take its integral
\[3x^2 \over 2x^3 - 5\] ?
Integrate by substitution.
is look a quotant rule to me
no. it's integration, not differentiation
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this is a log function let u = 2x^3 - 5 du/dx = 6x^2 1/2 du = 3x^2 so you are finding the antiderivative of \[\frac{1}{2} \int\limits \frac{du}{u} = \frac{1}{2} \ln( u) + c\]
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