Question

I need fast help! find y such that the distance between the points is 8. (5,1) (5,y)

Answer 1

Use the formula

\[\Large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}\]

Answer 2

I did that and got 64=0 + (1-y)^2.idk what happened..

Answer 3

In your case, d = 8, x1 = 5, x2 = 5, y1 = 1 and y2 = y

So

\[\Large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}\]

becomes

\[\Large 8 = \sqrt{\left(5-5\right)^2+\left(1-y\right)^2}\]

Answer 4

Now that you know that

64=0 + (1-y)^2

You can get rid of that 0 to get

64 = (1-y)^2

Answer 5

What's next?

Answer 6

umm....

Answer 7

sqrt?

Answer 8

yes

Answer 9

so 8=1-y? distance is 7?

Answer 10

no, the given distance is 8

Answer 11

what is the 7?

Answer 12

-7

Answer 13

8 = 1 - y

8 - 1 = -y

7 = -y

-y = 7

y = -7

Answer 14

So is that my answer

Answer 15

So the distance between (5,1) (5,-7) is 8 units

Answer 16

yes

Answer 17

thanks so much

Answer 18

sure thing