Question

Evaluate the integral
60e^(3.4x) (30,50)

Answer 1

\[\int 60e^{3.4x}dx \implies 60 \int e^{3.4x}dx\]

Answer 2

then what would be the next step?

Answer 3

then you integrate e^3.4x

Answer 4

its supposed to be 6e^(3.4x) btw my mistake

Answer 5

but the integral of that would be (5e*(17x/5))/17 then?

Answer 6

(5e^(17x/5))/17

Answer 7

yup..now multiply that by 30

Answer 8

i mean60

Answer 9

i meant 6 so 6 times that would be 300.1115556

Answer 10

but then where would the (30,50) come into play?

Answer 11

hmm where did you get that?

Answer 12

they are they constraints

Answer 13

\[60 \times \frac{5e^{17x/5}}{17}\]
\[\frac{60 \times 5}{17} \times e^{17x/5}\]

Answer 14

\[\int\limits_{30}^{50}\]

Answer 15

did you plug in the limits already?

Answer 16

no i havent

Answer 17

im not sure how

Answer 18

do \[\frac{60 \times 5}{17} \times e^{17x/5}\]
first

Answer 19

what is 60 x 5/17?

Answer 20

its supposed to be 6 lol that was my mistake from the beginning in my first post so its supposed to be 6* 5/17

Answer 21

ohhh

Answer 22

which is 1.764705882

Answer 23

yes

Answer 24

\[1.77 e^{17x/5}\]
now plug in the limits

Answer 25

how would i plug in the limits?

Answer 26

\[\large 1.77[e^{(17 \times 50)/5} - e^{(17 \times 30)/5}]\]

Answer 27

i have to go now sorry...hope you figure out what that means :D

Answer 28

but basically i just did \[\large [f(x)|_a^b \implies f(b) - f(a)\]

Answer 29

got that?

Answer 30

yeahh just coming up a huge number but i think i understand thanks

Answer 31

you're welcome! :)