Question

Evaluate the area of the region between the following curves for x in (-1,1)
y=4x^2+5
y=-3

Answer 1

looking to integrate right?

Answer 2

if that is how you find the area yes!

Answer 3

that is integrate
\[\int_{-1}^1(4x^2+8)dx\]
you know how to do this?

Answer 4

yes and i tried that but it said that answer wasnt right :/

Answer 5

what did you get as your answer?

Answer 6

18.66666667

Answer 7

ah that is why

Answer 8

not sure how you got it, but lets do it the easy way

\[\int_{-1}^14x^2dx+\int_{-1}^18dx\] second part is \(2\times 8=16\) from your eyeballs.

Answer 9

first part need the anti derivative of \(4x^2\) which is \(\frac{4}{3}x^3\)

Answer 10

soo how should i calculate the answer?

Answer 11

oh damn i get the same thing!!!

Answer 12

sorry i thought something was different
is this an on line homework?

Answer 13

yes

Answer 14

the answer is \(\frac{56}{3}\) if it is on line maybe you should just try the fraction

Answer 15

yes thats right thank you!!!!

Answer 16

what system are you using? it is possible that it doesn't like 18.33333...

Answer 17

you are welcome, but you did all the work. i just helped with the input

Answer 18

would you know this one?
y=e^x+5
y=9 ??

Answer 19

given no constraints

Answer 20

what exactly is the question?

Answer 21

area between the curves?

Answer 22

that can't be right because there is no area between the curves
what does the question ask?

Answer 23

yes thats what it is asking for

Answer 24

are you sure? because it doesn't make sense really. the region is not bounded in any way,

Answer 25

\(y=9\) is just a horizontal line, and \(e^x+5\) is an exponential curve
looks like this
http://www.wolframalpha.com/input/?i=y%3De^x%2B5%2Cy%3D9

Answer 26

so there is no region between the curves
maybe you could post the problem

Answer 27

i know thats why its given me trouble byt thx for tryin

Answer 28

yw