Question

write the following quandratic function in vertex form. y=x^2+2x-2

Answer 1

is this the same mathdummy4 that was asking about the closed form of \(\int e^{x^2}dx\)?

Answer 2

lol ya...kinda a long story..

Answer 3

to find the first coordinate of the vertex , use \(-\frac{b}{2a}\) in this case you get \(-\frac{2}{2\times 1}=-1\)

Answer 4

second coordinate of the vertex is what you get when you replace \(x\) by \(-1\) namely
\[(-1)^2+2\times (-1)-2=1-2-2=-3\]

Answer 5

vertex form is therefore \(y=(x+1)^2-3\)
not sure what the closed form is though...

Answer 6

that all im looking for..thanks satellite! you sure are a life-saver