HOW DO YOU DO THIS QUESTION? Choose the equation of the line passing through the point (-4, -2) and parallel to y = x + 2.
First off, what will the slope of a line that is parallel to y=x+2 be?
they have the same slope
Good, do you know how to use the point slope formula?
\[y-y _{1} = m(x-x _{1})\]
yea i think so
Y-(-2)=1(X-(-4))
Cool, now solve for y.
the equation for the question is y=1/4x +2
sorry!
Same principle. You know the slope will be the same. You've got a point on the line. Just plug and chug. :)
That makes more sense cause the other one would give you the same equation
The trickiest part of these is generally making sure that you change the signs as needed.
Yeah, I noticed that. I thought it might have been a trick question.
is it Y-(-2)=1/4 (X-(-4)?
Yup. Now just solve for y.
okk thanks alot
No problem. Please not that doing this for a line that was perpendicular is almost exactly the same, you've just got to find the slope of the new line. Remember when lines are perpendicular: \[m _{1} \times m _{2} = -1\]
is it y = 1/4x - 3
I'm getting y = 1/4x - 1
?????:(
Here's our point slope formula again: \[y-(-2)=1/4 (x-(-4)\] Distribute the 1/4: \[y+2=1/4x +1\] Subtract 2 from both side: \[y=1/4x -1\]
Gotta watch those sign changes :)
oh ok i get it yea i messed up with the signs but thanks alot :))))))))))))))))))))))))
Not a problem. :D Good luck!
Choose the equation of the line passing through the point (-4, -2) and perpendicular to y = -x + 6. is the answer to this y = -x +2??
The slope of a line perpendicular to y = -x + 6 is m=1. To get that, take the original slope, flip it upside down, and reverse the sign.
oh yea i forgot about that
I've got to run, but just to make sure you've got it. m=1 \[y-(-2)=1(x-(-4))\] \[y+2=x+4\] y=x+2
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