Question

Evaluate the integral
6e^(3.4x) with limits (30,50)

Answer 1

hmm looks familiar...wasnt able to solve it?

Answer 2

nope :(

Answer 3

why not?

Answer 4

not sure guess i couldnt figure it out. either that or i am incorrectly entering answers like 2.3745 x 10^76 into my online homework

Answer 5

if i even had the right answer

Answer 6

it was \[\huge 1.77e^{17x/6}\]
right?

Answer 7

yes

Answer 8

so now substitute 50 and 30

Answer 9

\[\huge 1.77 e^{\frac{17 \times 50}{5}} - 1.77e^{\frac{17 \times 30}{3}}\]

Answer 10

Yes,
\[\int\limits_{30}^{50}6e^{3.4x}=[\frac{6e^{3.4x}}{3.4}]_{30}^{50}\]

Answer 11

derp...that should be over 5 not 3

Answer 12

Power rule will do here

Answer 13

\[\huge 1.77 e^{17 \times 10} - 1.77 e^{17 \times 6}\]
i just canceled the thingies...did you get this?

Answer 14

lol big number

Answer 15

im still getting 2.386515463 x 10^75 soo is that right?

Answer 16

that's not what wolfram got

Answer 17

what did wolfram get

Answer 18

you may have had a syntax error

http://www.wolframalpha.com/input/?i=1.77+x+e%5E170+-+1.77+x+e%5E102

Answer 19

oh yeah well my hw is saying that that answer isnt correct either grrr

Answer 20

WHAT?!!!

Answer 21

http://www.wolframalpha.com/input/?i=int+6e%5E%283.4x%29+from+30+to+50

Answer 22

should be http://www.wolframalpha.com/input/?i=1.77+%28+e^170%29+-%28+1.77%29+%28+e^102%29
I think you put the 'times' incorrectly

Answer 23

im right o.O

Answer 24

well a little inaccurate but still!!

Answer 25

wait so witch should i put in as my answer?

Answer 26

Both are the same
http://www.wolframalpha.com/input/?i=int+6e^%283.4x%29+from+30+to+50
http://www.wolframalpha.com/input/?i=1.77+%28+e^170%29+-%28+1.77%29+%28+e^102%29
\[\int\limits_{30}^{50} 6 e^{3.4 x} \, dx=1.19326\times 10^{74}\]

Answer 27

do you know any other alternative forms for that answer?