Question

Help with integrating this question.

Answer 1

\[\int\limits_{\pi/6}^{\pi/3}\sec^2xdx \]

Answer 2

use this
\[\frac{d}{dx} (\tan x) =1+\tan^2 x=\frac{1}{\cos^2 x}=\sec^2 x\]

Answer 3

i got \[(2\sqrt{3})/2 \]
but my friend got \[2/\sqrt{3}\]

Answer 4

not sure which is right, because he is smarter than me lol.

Answer 5

(2√3)/3
my bad, over 3 not 2

Answer 6

u r completely right

Answer 7

(2√3)/3

Answer 8

okay sweet, is it because i rationalised the denominator?

Answer 9

ok