hey guys can you please help with this question... i'll post it up in a sec...
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OpenStudy (anonymous):
\[\log_{a} (x+y)= \log_{a}x + \log_{a}y \] Rewrite this relation in index form (that is without using logarithms)...
OpenStudy (anonymous):
What is your question can you explain it more to me??
OpenStudy (anonymous):
is it :
\[x + y = xy\]
OpenStudy (anonymous):
no you just have to find the relation between the two formulas by using indecies and no logarithms in the final answer.
OpenStudy (anonymous):
What do you mean by index form??
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OpenStudy (richyw):
\[\text{use } a^xa^y=a^{x+y}\]
OpenStudy (anonymous):
@waterineyes yes your answer was correct... can you please show me how you got it...
OpenStudy (anonymous):
See use the formula on right hand side:
\[Log_x(a) + Log_x(b) = Log_x(a b)\]
So,
\[Log_a(x + y) = Log_a(xy)\]
Taking Anti Logarithm both the sides,
\[x + y = xy\]
OpenStudy (anonymous):
so haha anti log? i get it sorta...
OpenStudy (anonymous):
Anti Log means reverse of log like anti derivative etc etc..
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