do i distribute the 70 in this problem
sqrt 70 (sqrt14)(sqrt22)
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OpenStudy (anonymous):
you can't simplify sqrt 70
OpenStudy (anonymous):
do i just multiply them all together
OpenStudy (anonymous):
try it
OpenStudy (anonymous):
the numbers to big
OpenStudy (anonymous):
its sqrt of 21560
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OpenStudy (anonymous):
yes, find factors of it that are perfect cubes, such as 4
OpenStudy (anonymous):
49 is a factor
OpenStudy (anonymous):
can be simplified into 7sqrt440
OpenStudy (anonymous):
14sqrt 10
OpenStudy (anonymous):
nvm thats wrong
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OpenStudy (anonymous):
14sqrt110
OpenStudy (anonymous):
right
OpenStudy (anonymous):
yes
OpenStudy (phi):
when you have
\[ \sqrt{70}\cdot\sqrt{14}\cdot\sqrt{22} \]
you can put the whole thing under one square root sign:
\[ \sqrt{70 \cdot 14\cdot 22} \]
to simplify this mess, break each number into its prime factors. (so you need to know what numbers are prime)
70= 2*5*7 (to find these, divide by 2 to get 35, then divide 35 by 5 to get 7)
14= 2*7
22= 2*11
now look for pairs (those we can pull out of the square root)
2*5*7*2*7*2*11 rearrange as 2*2*7*7 * 5*2*11
that means we can pull out square root of 2*2*7*7 to get 2*7
the answer is
\[ 2\cdot 7\sqrt{2\cdot5\cdot11} = 14\sqrt{110}\]