if a,b,c are positive and unequal.show that the value of the given determinant is negative.
I a b c I I b c a I I c a b I
Let's find the determinant \[\Delta=a(bc-a^2)-b(b^2-ac)+c(ab-c^2) \] Let's simplify it \[abc-a^3-b^3+abc+abc-c^3\] We get \[3abc-a^3-b^3-c^3\]
Let me think, how we can prove this to be always negative!!
okay..
ash look -a^3 = always negative -3^3 = -27 so i think its proved :)
That's correct but we need to prove that \[abc<a^3+b^3+c^3\] for all a's, b's and c's
take an example |1 2 3| |3 4 1| |4 2 1|
we need to find its negative value and thats with a prove.
No, just one example is not enough, we need to prove it for all real numbers
yah .. @ash2326 is right @annas guys help me plz
yeah i m trying
plz ..
http://www.scribd.com/doc/88441256/19/Applications-of-Determinants-and-Matrices check the example number 30
we'll have to perform little row and column operations
taht link is taking too much time ..
its a bit heavy site
@shruti if you want i can put a screen shot of the solution ?
yes sure. i think @ash2326 left.
ok give me a sec
fine
I'm here, I tried something but it wasn't correct :'(
:(aww...
check the attachment
no worries ash :) you did the best help you are the most awesome helper
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