Question

\[\frac{(\log_{}{x}-\log_{}{y} )(\log_{}{x^2}+\log_{}{y^2} )}{(\log_{}{x^2}-\log_{}{y^2} )(\log_{}{x+y} )}\] is equal to????

Answer 1

\[\log{x} + \log{y} = \log{xy}\]\[\log{x}-\log{y} = \log\frac{x}{y}\]
Is the denominator \(\log{x}+\log{y} \)? instead of \(\log{x}+y\)

Answer 2

\[\frac{\log(\frac{x}{y}) \times \log(x^2y^2)}{\log(\frac{x^2}{y^2}) \times \log(xy)} \implies \frac{\log(\frac{x}{y}) \times 2\log(xy)}{2\log(\frac{x}{y}) \times \log(xy)} \implies 1\]

Answer 3

\[\large \log{x} + \log{y} = \log{xy}\]

\[\large \log{x}-\log{y} = \log\frac{x}{y}\]

I have used this formulas in first step..

\[\large loga^b = b \times \log(a)\]

In second step I have used this...

Answer 4

i used all this formulas but i didn't gt the answer @waterineyes :(

Answer 5

I have solved it answer is 1..

Answer 6

\[\LARGE{Ans:1}\]

Answer 7

so plz give me full solution

Answer 8

See above i have solved it..

Answer 9

oh! ya i gt it. Thanx a lot:)

Answer 10

Welcome dear..