There are 5 lollipops. Once a day, Joe licks on only one of them per day, and does this for 5 days straight. What is the probability that Joe did not lick on exactly 1 of the lollipops?
that is way way wrong. nvm
have to think more
I got \[(1 \times \frac{4}{5} \times \frac{3}{5} \times \frac{2}{5})(\frac{4}{5} = \frac{96}{625})\]
Sorry I put the parenthesis in the wrong place, but nonethless 96/625
that looks much better than what i wrote
Why is math so hard
these problems are hard to wrap your mind around
The second time he chooses to lick a lollipop, does he still have 5 lollipops to choose from or is it 4?
still thinking lets put one lollipop aside and then see if we can figure the probability that he picks each one of the other 4
Condition 1) 1st: 5 choices 2nd: 4 choices 3rd: 3 choices 4th: 2 choices 5th: 4 choices Therefore \[\frac{5 \times 4^2 \times 3 \times 2}{5^5}\]
looks good to me
Wow, are you joking? I was typing a long response and I clicked 'Back' by accident and it erased my entire reply
annoying isn't it?
Well, I guess I will just guess on this question
i feel useless, but i am sure this is not that hard
I'm the worst math major ever
you should have seen me!
i think your answer looks good though is this one of those annoying "sterling number" problems?
*stirling
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