Question

(d^2y)/(dx^2) of sqrt(y) + xy = 1. I can get the 1st implicit derivative, but I lose it somewhere on the 2nd.

Answer 1

show the first one then

Answer 2

for dy/dx I get - (y)/(1/2sqrt(y) + x)

Answer 3

sqrt(y) + xy = 1

1/2sqrt(y) y' + x'y + xy' = 0

since x' = dx/dx in this case, that goes to 1

1/2sqrt(y) y' + y + xy' = 0

y'(1/2sqrt(y) + x) = -y

y' = -y/(1/2sqrt(y) + x)

Answer 4

Hi Ajk :)

How are you friend ?

Answer 5

you can either go ahead from the unsimplified y'; or this one :)

Answer 6

@mahmit2012 I think he is asking for implicit differentiation.
amistre64 is doing right.