Question

Sketch the vector field F by drawing a diagram
F(x,y)= (yi-xj)/sqrt(x^2+y^2)
Table:
x y sqrt(x^2+y^2)
1 1 sqrt (2)
1 2 sqrt (5)
1 3 sqrt (10)
1 4 sqrt (17)
1 5 sqrt (26)
2 1 sqrt(5)
3 1 sqrt(9)
4 1 sqrt (17)
5 1 sqrt (26)

Answer 1

I forgot to complete the table.

Answer 2

So it looks like your vector will have an i component and a j component as determined by that function. It would probably be useful to add an i column to your table and a j column.

Answer 3

The i component will just be y/sqrt(x^2+y^2), and you already have the denominator determined in your 3rd column there.
The j component will just b -x/sqrt(x^2+y^2)

Answer 4

Do you see what I'm tryin' to say, or is just jibberish?

Answer 5

I understand that I need to make a column for the i and j components. Would I label that column as i and j, and their values would be -x/sqrt(x^2+y^2) and y/sqrt(x^2+y^2) respectively?

Answer 6

*those columns

Answer 7

Look again at your function:
\[\frac{yi-xj}{\sqrt{x^2+y^2}}\]
Break that up into two fractions so that it's easy to see which part is i and which part is j
\[= \frac{y}{\sqrt{x^2+y^2}}i -\frac{x}{\sqrt{x^2+y^2}}j\]

Answer 8

Thanks for your help.

Answer 9

My pleasure! =D

Answer 10

Where is my medal?

Answer 11

lol

Answer 12

Thank You