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help fast! Find the 5th term of the geometric sequence 9, 27, 81,…
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GS terms are a, ar, ar^2 ... a = first term, r = common ratio
use the formula \[T_{n} = ar^{n -1}\] a = 9 and r = 3 n = 5
i tried, what would the fifth term be?
9 * 3^4
\[T_{5} = 9\times3^{5 -1}\] so \[T_{5} = 9 \times 3^4\] here is a calculator you can use http://web2.0calc.com/
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9* 3^4 can u just do that? trust me i know how to tho
well its 9 x 3 x 3 x 3 x 3= 9 x 81
81x9?
yep that 9 x 80 + 9 x 1 =
279??
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is that my answer?
close... swap the first 2 digits
729 oops!
thats the answer
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