Mathematics
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OpenStudy (anonymous):
Solve the equation by completing the square:
x2 + 2x = 3
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OpenStudy (anonymous):
x^2 + 2x + 1/4 = 3 + 1/4
OpenStudy (anonymous):
X²=√X²,X=1 i got this as an answer
OpenStudy (anonymous):
i think im completing it right hang on
OpenStudy (anonymous):
okay thanks
OpenStudy (anonymous):
wait plus 1
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OpenStudy (anonymous):
x^2 + 2x (+1) = 3 (+1)
OpenStudy (anonymous):
then you'll get (x+1)^2 = 4 and that's your answer
OpenStudy (anonymous):
i need to find what the two x"s are
OpenStudy (anonymous):
its 1 or -3
OpenStudy (anonymous):
since (1+1)^2 = 4 and (-3+1)^2 both equal 4
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OpenStudy (anonymous):
okay i understand now thank you(:
OpenStudy (anonymous):
yep np
OpenStudy (anonymous):
to find it usually you'd sqrt both sides just remember the answer can be pos or neg and solve
OpenStudy (anonymous):
WAITTTTTT
OpenStudy (anonymous):
?
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OpenStudy (anonymous):
12 Answer:
Solve the equation by completing the square:
x2 + 8x = 14
OpenStudy (anonymous):
x^2 + (8x) + ? = 14 + ?
OpenStudy (anonymous):
you are very smart @funkeemonk3y
OpenStudy (anonymous):
then x^2 + 8x + 16 = 14 + 16
OpenStudy (anonymous):
then you'd have (x+4)^2 = 30
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OpenStudy (anonymous):
were do you get 16 from?
OpenStudy (anonymous):
note for completing the square its generally a^2x + bx + c to be a complete square c = (b/2)^2
OpenStudy (anonymous):
in order to compete the square thats the main concept you must make it into the form (x + a)^2 = #
OpenStudy (anonymous):
note that (a+b)^2 = a^2 + 2ab + b^2
OpenStudy (anonymous):
gotta go hope this helps
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OpenStudy (anonymous):
Thank you!!!
OpenStudy (anonymous):
HELP
OpenStudy (anonymous):
x^2+2x+1/4=3+1/4