y=x(x^2+y^2)
use distributive property
should i expant first the equationinside the parenthesis? it is differential equation.
where;s the differential?
do you mean y' = x(x^2 + y^2)?
yes. please help me.
what methods are you familiar with? are you familiar with the bernoulli's equation?
yes i am but why should i use bernoulli? its for physics.
please help me. i have a confusion in using the product rule in differential.
lol anything else you wanna say? =))) you're suddenly revealing a lot of new info
nothing else i thought. how can i fairly understand product rule in DC? i try using it but i didnt arrived at the correct answer.
hmm im not an expert on this field so maybe @UnkleRhaukus can provide info..
thanks for the help. =]]
So this is your question? \[y^\prime=x(x^2+y^2)\]\[y(x)=?\]
yes it is. please help me. to solve that.
\[y^\prime=x(x^2+y^2)=3\]?
help me please
im not sure if i can help you
oh. could you please try?
can you tell me where the equation has come from , what it describes
find the derivative of the given equation. it will use product rule in differential calculus. i tried it but i attain different answer. i have a confusion by dealing with it.
oh. well now your asking something different,
This is your question\[y=x(x^2+y^2)=3\]\[y^\prime=?\]
\[y=x^3+xy^2\]\[y^\prime=3x^2+y^2+2xyy^\prime\]\[y^\prime(1-2xy)=3x^2+y^2\]\[y^{\prime}=\frac{3x^2+y^2}{1-2xy}\]
thanks a lot @UnkleRhaukus ! you're a big help or me! More power! =]]
im still not sure what to do with the three
it okay. youre answer has a great help for me. now i truly understand it. Thanks! 3 will become O cause its a constant. ((=
ok
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