log(x+1)=5; solve for x

Question

mimi_x3 · Answer

Write it as; $log_e(x+1)=5$
=> $(x+1)= e^{5}$

mimi_x3 · Answer

Are you able to do it now?

lgbasallote · Answer

some prefer 10 instead of e though...especially in common logarithms

anonymous · Answer

how do i type it in a calculator?

helder_edwin · Answer

@Mimi_x3 why did you assume the base of log is e?

lgbasallote · Answer

i think she's had too much of calculus =))

mimi_x3 · Answer

Because it's easier to see for the RHS because the other side must be $e$. That was what I learnt lol.
@lgbasallote: it wont make sense if its $10$

lgbasallote · Answer

common logarithms..

lgbasallote · Answer

$$log a \implies \log_{10} a$$
$$\ln a \implies \log_e a$$

mimi_x3 · Answer

What is that? Care to refresh my mind. Haven't touched loagarithms in a while..

mimi_x3 · Answer

It's the same thing lol

mimi_x3 · Answer

log_10(a) = log_e

lgbasallote · Answer

common logarithms are logarithms with no base. it is impicit that the base is 10

lgbasallote · Answer

yes @Mimi_x3 like i said "prefer" i didnt say it was wrong

mimi_x3 · Answer

why is it called "common log"

mimi_x3 · Answer

wait..if you did log_10 instead; it wont make sense..

lgbasallote · Answer

lgbasallote · Answer

everything will make sense after you read that

mimi_x3 · Answer

lol like i have the time to :P

lgbasallote · Answer

well you're here arent you

mimi_x3 · Answer

"log10(x) should be lg (x) and loge(x) should be ln (x)."-  it's the same lol