Question

Steps to solve: 3X^2+9x+6=0

Answer 1

divide each term by 3 first. it will make your life easier

Answer 2

Done that - would using the quadratic formula make it easier - is there another way to do it without using quadratic formula

Answer 3

sure why not

Answer 4

though you may want to know it's facctorable

Answer 5

but yeah...to be sure quadratic formula may be better

Answer 6

\[3x^{2}+9x+6\]
\[3(x^2+3x+2)\]
a*b = 2 * 1
a+ b = 2+1
\[ 3(x+1)(x+2)\]

Answer 7

you can just get rid of the 2 @Mimi_x3 lol

Answer 8

why waste latex :p

Answer 9

what 2?

Answer 10

so if you were doing it without the quadratic formula what would be the steps to doing it ?

Answer 11

i meant 3

Answer 12

how do you get rid of it?

Answer 13

like i said divide by 3 so you ended up with x^2 + 3x + 2 right?

Answer 14

so a = 1
b = 3
c = 2

Answer 15

lol woops i forgot about the 0

Answer 16

\[x = \frac{-3 \pm \sqrt{(3)^2 - 4(1)(2)}}{2(1)}\]
\[x = \frac{-3 \pm \sqrt{9 - 8}}{2}\]
\[x = \frac{-3 \pm \sqrt 1}{2}\]
\[x = \frac{-3 \pm 1}{2}\]

Answer 17

so \[x = \frac{-3 + 1}{2} \; ;\; \frac{-3 - 1}{2}\]
\[x = \frac{-2}{2} \; ;\; \frac{-4}{2}\]

Answer 18

Thank you! - i understand now - i had made a mistake right up in the begining which is why i got it wrong. Thanks

Answer 19

you're welcome :D