Ask
your own question, for FREE!
Mathematics
68 Online
OpenStudy (anonymous):
Given the function f(x) = 2x +4 find the value of f(1/2).
A. 5
B. 4 ½
C. 6 ½
D. 6
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Put \(x = \frac{1}{2}\) in the function..
jimthompson5910 (jim_thompson5910):
\[\Large f(x) = 2x + 4 \]
\[\Large f\left( \frac{1}{2} \right ) = 2\left( \frac{1}{2} \right ) + 4 \]
jimthompson5910 (jim_thompson5910):
I'll let you finish
OpenStudy (anonymous):
After solving what you got @suckatmath17
OpenStudy (anonymous):
i really have no clue what to do...
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
sorry
jimthompson5910 (jim_thompson5910):
2 times one-half is ???
OpenStudy (anonymous):
do i just times the bottom half of the fraction with 2?
jimthompson5910 (jim_thompson5910):
So
\[\Large f(x) = 2x + 4 \]
\[\Large f\left( \frac{1}{2} \right ) = 2\left( \frac{1}{2} \right ) + 4 \]
\[\Large f\left( \frac{1}{2} \right ) = 1 + 4 \]
jimthompson5910 (jim_thompson5910):
sry made a typo
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
im sorry i still dont get this at all!:(
jimthompson5910 (jim_thompson5910):
\[ \Large 2 \times \frac{1}{2} \]
\[ \Large \frac{2}{1} \times \frac{1}{2} \]
\[ \Large \frac{2 \times 1}{1 \times 2} \]
\[ \Large \frac{2}{2} \]
\[ \Large 1\]
So \[ \Large 2 \times \frac{1}{2} = 1 \]
jimthompson5910 (jim_thompson5910):
Hopefully you now see how 2 times one-half is 1?
OpenStudy (anonymous):
yes i do thanks
jimthompson5910 (jim_thompson5910):
So this means...
\[\Large f(x) = 2x + 4 \]
\[\Large f\left( \frac{1}{2} \right ) = 2\left( \frac{1}{2} \right ) + 4 \]
\[\Large f\left( \frac{1}{2} \right ) = 1 + 4 \]
\[\Large f\left( \frac{1}{2} \right ) = 5 \]
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
oh my gosh thanks soooo much
jimthompson5910 (jim_thompson5910):
you're welcome
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
MAGABACK:
ART!
4 hours ago
5 Replies
0 Medals