Question

The solution to the radical function square root of the quantity one half x plus one equals one is x = 0

Answer 1

true or false?

Answer 2

is this
\[ \large \sqrt{\frac{x}{2}+1}=1 \]
correct?

Answer 3

\[\sqrt{\frac 12 x + 1} = 0\]
to solve for the zero of this square both sides to get rid of thesquare root
\[(\sqrt {\frac x2 + 1})^2 = 0^2\]
\[\frac x2 + 1 = 0\]
now subtract 1 from both sides
\[\frac x2 = -1\]
now multiply 2 to both sides
\[\frac x2 \times 2 = -1\times 2\]
\[x = -1 \times 2\]

Answer 4

do you think this is 0?

Answer 5

@lgbasallote you forgot the "equals 1" of the statement

Answer 6

where does it say it is equal 1?

Answer 7

oh yeah

Answer 8

lemme redo that

Answer 9

\[\sqrt{\frac x2 + 1} = 1\]
square both sides
\[(\sqrt{\frac x2 + 1})^2 = (1)^2\]
\[\frac x2 + 1 = 1\]
subtract 1 from both sides
\[\frac x2 + 1 - 1 = 1 - 1\]
\[\frac x2 = 0\]
multiply 2 to both sides
\[\frac x2 \times 2 = 0\times 2\]
\[x = 0 \times 2\]
do you think this equals 0?

Answer 10

say something @iceywheniplease7

Answer 11

yes?