Question

find the radius of the circle with these three points (-3-5),(-9,-5),(-6,-2) and center (-6,-5)

Answer 1

find distance from center to any one of the 3 points on circle... lgba.. i think this is 2D only

Answer 2

lol yeah =)) sorry

Answer 3

i guess the 3rd point gives a diffrent answer (-6,-2)

Answer 4

you can use the distance forumula : \(\sqrt{(x2-x1)^2+(y2-y1)^2}\)

Answer 5

yeah thats right with any of the point

Answer 6

yeah

@Colocha can you find the radius using distance formula ?

Answer 7

um i gt 2.449

Answer 8

its probably wrng

Answer 9

o i messed up

Answer 10

hmm
which two points you took... .one point must have to be center, other can be any of the three

Answer 11

o ok ill do it again

Answer 12

np good luck :)

you should get 3 maybe

Answer 13

actually u have to take the radius and any one point along with it

Answer 14

i gt three i choose (-9,-5) and the center

Answer 15

i mean the center

Answer 16

yeah then ur right good job

Answer 17

ook now this one find the radius of the circle defined by the equation
x^+y^2-10x+4y+4=0

Answer 18

please post it in other link

Answer 19

okay

distance between (-6, -5) and (-9, -5) =
\(\sqrt{(-6-(-9))^2+(-5-(-5)^2)}\)
\(\sqrt{(-6 + 9)^2+(-5 + 5)^2}\)
\(\sqrt{(3)^2+(0)^2}\)

= ?

Answer 20

to find the radius of x^+y^2-10x+4y+4=0 ---------(1)

rearrange the equation in standard form :
(x-h)^2 + (y-k)^2 = r^2 ---------------------(2)

"r" is the radius

Answer 21

idk how to do that

Answer 22

Ok. its somewhat tricky to arrange the equation in standard form. pls post it in a new thread... il see if i can help :))

Answer 23

its on a new thread