Question

find a polynomial function f(x) for the second degree when f(0) =4 , f(-1) = 3 , f(1) =9 .

Answer 1

f(x) = 2x^2 + 3x +4

Answer 2

@Vaidehi09 Dont just give the answer. It is against the Code of Conduct. Guide the asker to the answer

Answer 3

yes please ..

Answer 4

f(x)=a*x^2+b*x+c
we must find a,b and c
f(0)=4.....a*0^2+b*0+c=c=4
f(-1)=3....a-b+4=3...a-b=-1
f(1)=9.......a+b+4=9...a+b=5
2a=4and 2b=6
then ; a=2 and b=3 c=4
f(x)=2x^2+3x+4

Answer 5

here's how:
let f(x) = ax^2 + bx + c.........(i)
we're given that f(0) = 4. so sub x = 0 in (i)
f(0) = 0 + 0 + c
4 = c........(ii)

now we know that f(-1) = 3. sub that in (i).
f(-1) = a(1) - b + 4.......from (ii)
3 = a - b + 4
b = a+1.........(iii)

next, we know f(1) = 9. sub that in (i).
f(1) = a + b + 4..........from (ii)
9 = a + a+1 + 4........from (iii)
4 = 2a
a = 2.
sub this in (iii)
u'll get b = 3.

sub values of a, b , c in (i) and u'll have ur answer.

Answer 6

thank you @Vaidehi09

Answer 7

glad to be of help! :)