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Find the value of the expression squar root of A^2 + 6^2 - 7^2 if a = 8 and b = 7
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where is b???
is the 6 in the exp actually b?
ya where is b
soory i ment to put squar root of A^2 + 6^2 - B^2
64+36-49
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just substitute the values in the expression then. what's the confusion?
=51
when i did the problem i got 51 then i sq and got 7.14 and its not an anser so i think i messed up some were
\[a^{2}+6^{2}-b^{2}\] putting values \[8^{2}+6^{2}-7^{2}\] \[64+36-49\] = \[\sqrt {}\]
=sqrt (51)
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what's the final answer given as?
=8^2+6^2-7^2 =64+36-49 =651 take sq root of it =25.51 25.51 is the answer
Check your solution once again @Qibtiya .
put the given values in the equation as\[a^2+6^2-7^2\]\[8^2+6^2-7^2\]\[64+36-49=?\]
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