Question

find any intercepts. y=x^2+3x / (3x+1)^2

Answer 1

please!

Answer 2

\[y = \frac{x^2 + 3x}{(3x + 1)^2}\]

Answer 3

yes, I thought you start off setting y to 0, then finding those intercepts?

Answer 4

but I'm not sure how to simplify the right

Answer 5

ok when x =0 u fin b and when y=o u find a

Answer 6

Just factor the top:
\[y = \frac{x(x + 3)}{(3x + 1)^2}\]

Answer 7

You can find the x-int when x = 0, so that equation will become 0 when the numerator is 0. So find the solutions in the numerator, and you'll have your x-intercepts. Remember the domain also because the denominator can't be 0 or it'll become undefined

Answer 8

but how would I find the y?

Answer 9

Just plug in 0 for the x-values and the number you get is the y-intercept

Answer 10

So plug in 0 for all x values.. then what I get is the y? let me try and tell you what i get

Answer 11

is it 0?

Answer 12

Yup

Answer 13

So y is (0,0)

Answer 14

how would i find x?

Answer 15

Set the numerator I gave you above to 0 and find each x-value that will satisfy the value to be 0

Answer 16

can u explain?

Answer 17

i thought you set y to 0..then solved

Answer 18

The numerator factored is x(x + 3), right? So set each x to 0 and you have two equations to solve:

x = 0 and x + 3 = 0

Those will be your x-intercepts

Answer 19

Ok what about the denominator

Answer 20

so I have y= (0,0) and x = 0, -3

Answer 21

The denominator doesn't matter because whatever the denominator is, it won't make the equation 0. Just make sure it doesn't become undefined, that's all

Answer 22

Ok so is what I have above correct? like is that the answer

Answer 23

Those are your 3 intercepts, yes