The polynomial 6xy + 3y – 4x – 2 can be factored into (2x + 1) times
Do you know polynomial division?
What you have to do is: \(\Large {6xy + 3y - 4x - 2 \over 2x + 1}\)
Wasn't taught polynomial division in school my teachers were really ancient.
2x + 1 and 2x + 2?
so it looks like its 3y-2
Oopsie
you factored wrongly but it is factorable
\( \color{Black}{\Rightarrow 3y(2x +1) - 2(2x + 1)}\)
6xy - 4x + 3y - 2 (6xy - 4x) + (3y - 2) 2x(3y - 2) + (3y-2) (3y-2)(2x + 1)
\( \color{Black}{\Rightarrow (3y - 2)(2x + 1)}\)
Now you cancel them.
Ah okay. So since what Lgba did, I think he distributed correct?
So yeah, it does look like \(3y - 2\).
it works any way lol
He did. I just committed a mistake in between.
But do you get it now?
i was just proposing an alternate factoring :) to show what is the result
Yeah I think I have it down now. Thanks a lot
Weird how you still get the solution correct, despite the wrong method :P
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