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Mathematics 22 Online
OpenStudy (ledah):

The polynomial 6xy + 3y – 4x – 2 can be factored into (2x + 1) times

Parth (parthkohli):

Do you know polynomial division?

Parth (parthkohli):

What you have to do is: \(\Large {6xy + 3y - 4x - 2 \over 2x + 1}\)

OpenStudy (ledah):

Wasn't taught polynomial division in school my teachers were really ancient.

OpenStudy (lgbasallote):

2x + 1 and 2x + 2?

OpenStudy (ledah):

so it looks like its 3y-2

Parth (parthkohli):

Oopsie

OpenStudy (lgbasallote):

you factored wrongly but it is factorable

Parth (parthkohli):

\( \color{Black}{\Rightarrow 3y(2x +1) - 2(2x + 1)}\)

OpenStudy (lgbasallote):

6xy - 4x + 3y - 2 (6xy - 4x) + (3y - 2) 2x(3y - 2) + (3y-2) (3y-2)(2x + 1)

Parth (parthkohli):

\( \color{Black}{\Rightarrow (3y - 2)(2x + 1)}\)

Parth (parthkohli):

Now you cancel them.

OpenStudy (ledah):

Ah okay. So since what Lgba did, I think he distributed correct?

Parth (parthkohli):

So yeah, it does look like \(3y - 2\).

OpenStudy (lgbasallote):

it works any way lol

Parth (parthkohli):

He did. I just committed a mistake in between.

Parth (parthkohli):

But do you get it now?

OpenStudy (lgbasallote):

i was just proposing an alternate factoring :) to show what is the result

OpenStudy (ledah):

Yeah I think I have it down now. Thanks a lot

Parth (parthkohli):

Weird how you still get the solution correct, despite the wrong method :P

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