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Mathematics 16 Online
OpenStudy (anonymous):

can anyone help me with calculus

OpenStudy (anonymous):

It's possible. The business half is pretty weak up in here, but there are a bunch of calculus ballers hangin' around.

OpenStudy (anonymous):

let f(x)=2x cubed-4x find f'(-2) f'(0) f'(2)

OpenStudy (anonymous):

\[f(x) = 2x^3-4x\]

OpenStudy (anonymous):

Is that right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Alright, let's start with the basics, my little Grap buddy. Power rule! When we derive something that is just a power of x, maybe with a coefficient also, we have a really simple rule for what the result is. First, you take the exponent and multiply that with the coefficient to get your new coefficient. Next, you subtract one from your exponent to get your new exponent. Done. Super simple.

OpenStudy (anonymous):

So here's a quick example: \[f(x) = 6x^5\] \[f'(x) = 6*5x^{5-1} = 30x^4\]

OpenStudy (anonymous):

Understand? Ask me questions. Try this simple one. What's the derivative of 3x^3

OpenStudy (anonymous):

I understand that but the question involves the f'(-2) and f'(0) f' (2)

OpenStudy (anonymous):

Okay, so if you understand the differentiating part, then you know the hard part of the problem.

OpenStudy (anonymous):

Basically, all we have to do is differentiate f(x) to get f'(x) and then, since they are asking me f'(-2), I just plug in -2 and solve.

OpenStudy (anonymous):

I plugged it in and got 24 but that seems wrong

OpenStudy (anonymous):

I believe you took the derivative wrong. What did you get as f'(x)?

OpenStudy (anonymous):

24

OpenStudy (anonymous):

No no. The FUNCTION. f'(x) should be a function, you know, with x in it and whatnot.

OpenStudy (anonymous):

2x cubed-4x

OpenStudy (anonymous):

That's f(x). I need to know what you got for f'(x)

OpenStudy (anonymous):

I got 24 if f'(-2)

OpenStudy (amistre64):

you forgot to include the derivative of -4x then

OpenStudy (amistre64):

(2x^3)'(-2) = 24

OpenStudy (anonymous):

I am sorry I do not understand

OpenStudy (amistre64):

then show us what you get for f'(x)

OpenStudy (anonymous):

The answer is 20 but when I plugged in -2 to the function I dd not get the nswer 20

OpenStudy (amistre64):

the derivative of (2x^3 - 4x) is not 24

OpenStudy (anonymous):

Grap, can we just talk about functions really quick. YOu have a function f(x). It's a fancy thing that you can plug different values of x into. You take it's derivative and you get another function f'(x). It's still a fancy thing for plugging x values into. We're asking you for f'(x), a function, and you're giving us NUMBERS.

OpenStudy (amistre64):

i think you only took the derivative of the first part of it; or mistook the -4x as -4.

OpenStudy (anonymous):

I do not know how to find the f' function that is whT THEY ARE ASKING ME FOR

OpenStudy (amistre64):

how do you get 24 then?

OpenStudy (anonymous):

what sorry

OpenStudy (anonymous):

I plugged in the -2 into the function and I got -8 sorry

OpenStudy (amistre64):

in order to help you out, we have to know how it is that you tried to work the problem; otherwise we are just giving out an answer that has no study value

OpenStudy (amistre64):

derivatives follow a few basic principles that can be adhered to; but they have to be memorized to be useful :)

OpenStudy (anonymous):

Grap, I think it would be helpful for you to watch me work an example problem. The problem is: f(x) = 5x^3, find f'(1), f'(2), f'(3) Okay, so the first thing to notice is that they are asking for f'(1), not f(1). Do you see the difference?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

If it was f(1), I would plug 1 into f(x) but since it's asking for f'(1), I need to plug 1 into f'(x) f'(x) is a different function from f(x)

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

But we don't have the function f'(x). So our first step is to GET THAT FUNCTION. How do we get f'(x)? Well, f'(x) means the derivative of f(x), so we will take the derivative.

OpenStudy (anonymous):

f(x) = 5x^3 To take the derivative of that, we follow our derivative rule. Multiply by the power, then take the power down by 1. 5*3 = 15, so that's the new coefficient 3-1 = 2 so that's the new power f'(x) = 15x^2

OpenStudy (anonymous):

Make sure you understand that. That is the most important part of the problem. I had f(x). I took the derivative to get f'(x)

OpenStudy (anonymous):

Ask me questions.

OpenStudy (anonymous):

Ok so what about the -4x

OpenStudy (anonymous):

If our function has different terms, we can go through and use the same rule on each one of them.

OpenStudy (anonymous):

Here's an example f(x) = 3x^3 + 5x^2 +2x - 9 f'(x) = 9x^2 +10x +2 I used the power rule on the first 3 parts separately.

OpenStudy (anonymous):

And the last part is a constant, so the derivative is 0.

OpenStudy (anonymous):

no i mean my first question was f(x) 2x cubed -4x

OpenStudy (anonymous):

You have to understand, what I'm doing is called modelling. You watch me work an example, and you see how it's done. Then you can go and do other problems on your own.

OpenStudy (anonymous):

i understand that and I did what you did for my problem but I do not get the answer 20 so I want to find out what I did wrong

OpenStudy (anonymous):

-_-

OpenStudy (anonymous):

Grap, please understand my frustration. I'm telling you that the important part of the problem is finding f'(x) and you constantly ignore that and try to jump to the answer.

OpenStudy (anonymous):

I got it

OpenStudy (anonymous):

I understand give me a problem

OpenStudy (anonymous):

f(x) = 4x^3 +x^2 +9x What is f'(x)?

OpenStudy (anonymous):

12x squared+2x+9

OpenStudy (anonymous):

Good. What is f'(-2)?

OpenStudy (anonymous):

53

OpenStudy (anonymous):

What is f(-2)?

OpenStudy (anonymous):

-54

OpenStudy (anonymous):

Pretty close. The x^2 would be +4, not -4, so the answer is -46.

OpenStudy (anonymous):

In any case, I think you're right. You understand it. Just get a buncha practice with it now.

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

My pleasure, buddy! =D

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