Question

Can someone please up I just can not seem to set this problem up right.
Solve the triangle. Round lengths to the nearest tenth and angle measure to the nearest degree.
a=7, b=7, c=5

Answer 1

law of cosines for this one

Answer 2

if you have not got there yet i guess we can solve using some geometry

Answer 3

so you use a^2 + c^2 - b^2 / 2ac

Answer 4

you have the sides, so i take it you are looking for the angles right?

Answer 5

yes

Answer 6

if you want to use the law of cosines, use \(\cos(\theta)=\frac{a^2+b^2-c^2}{2ab}\)

Answer 7

I used a^2 + c^2 - b^2 / 2ac and got 5/14 but I don't know what to do now

Answer 8

take the inverse cosine

Answer 9

so use cos^-1 on my calulator

Answer 10

yes

Answer 11

so B = 69 degrees

Answer 12

yes

Answer 13

so two angles are 69 and the other is whatever \(180-2\times 69\) is

Answer 14

okay thank you I can figure the rest out i was using cos instead of the inverse

Answer 15

actually \(69.08\) if you want to be picky

Answer 16

yw