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Mathematics 9 Online
OpenStudy (anonymous):

x/3+x/4=1

OpenStudy (anonymous):

multiply both sides by 12 to clear the fraction then divide both sides by 7

OpenStudy (anonymous):

i dont understand i see were you got 12 but where did you get 7?

OpenStudy (anonymous):

you will see where i got it when you multiply both sides by 12

OpenStudy (anonymous):

hint, what is \(3+4\)?

OpenStudy (anonymous):

\(12(\frac{x}{4}+\frac{x}{3})=12\times 1\) \[3x+4x=12\] etc

hero (hero):

\(\frac{x}{3} + \frac{x}{4} = \frac{4}{4}\) \(\frac{x}{3} = \frac{4}{4} - \frac{x}{4}\) \(\frac{x}{3} = \frac{4-x}{4}\) 4x = 3(4-x) 4x = 12 - 3x 7x = 12 Finish the rest

OpenStudy (anonymous):

okay thank you both I get it now

hero (hero):

My method is easier

OpenStudy (anonymous):

could be, but not for me i think easier is in the eye of the beholder we could count steps maybe

hero (hero):

The steps are irrelevant. I only included all of them for demonstration purposes.

OpenStudy (anonymous):

in one sense they are because you can probably do this in your head, so in your mind and mine maybe no steps are required but you have to do some thinking and that counts as steps

OpenStudy (anonymous):

here is what i was thinking "least common multiple of 3 and 4 is 12 if i multiply both sides by 12 i get 3 + 4 = 7 x on the left, and 12 on the right now to get x i must divide by 7"

hero (hero):

You assume everyone would know how to find an LCM. For more difficult problems, finding an LCM would get difficult. My version offers an alternative to finding an LCM.

OpenStudy (anonymous):

i agree that your version works, i will leave it to others to decide what is "easiest"

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