How to solve: square root of r+4 + the square root of 2 is equal to 2?

Question

lgbasallote · Answer

$$\sqrt{r+4} + \sqrt 2 = 2$$
yes?

anonymous · Answer

put the sqrt 2 on the other side and square both sides

anonymous · Answer

square both sides.
$$(\sqrt{r+4}+\sqrt{2})^{2}=2^{2}$$
$$r+4+2+2(\sqrt{r+4})(\sqrt{2})=4$$...........by applying identity.
$$r+6+2({r+4})({2})=4$$
$$r+6+{4r+16}=4$$
$$5r+20=4$$
$$5r+20-20=4-20$$
$$5r=-16$$
$$r=\frac {-16}{5}$$

anonymous · Answer

I am working on other types of equetions, equations with two radicals. I was trying to facro 5r+16=0 to get two answers. In this case I have only one solution?? Can a solution of radical be negative?

anonymous · Answer

never

anonymous · Answer

sol. of  a radical is always positive.

anonymous · Answer

so this equation has no solution?

anonymous · Answer

or if this checks into the equation i can say this satisfy the equation?