Question

solve the following equation
in(2x + 1) = 10 ??? how do i do this

Answer 1

Is that a natural logarithm?

Answer 2

idk

Answer 3

I think he means ln(2x + 1) = 10

Answer 4

yea

Answer 5

The L looks Iike an i

Answer 6

oh sorry

Answer 7

That's the first time I've seen anyone do that.

Answer 8

do you know how to solve it?

Answer 9

Yup

Answer 10

(e^10 - 1)/2

Answer 11

@MrMoose, posting that alone doesn't provide much of an explanation for @tutorme

Answer 12

sorry
I joined a few minutes ago

Answer 13

any way

Answer 14

can you explain how you got that cause i don't know how you started

Answer 15

raise both sides to the e power to get rid of ln
subtract both sides by 1
divide both sides by 2

Answer 16

a logarithm is just a measure of what you have to raise something to to get that number

Answer 17

the number inside the parenthesis

Answer 18

so raising e to the natural log of something by definition gives you that something

Answer 19

I see what the problem is now @MrMoose. Ideally, it would be best if you began with some general formula when explaining these.

Answer 20

so e^ln(u) = u
where u is some expression

Answer 21

@Hero what is the formula?

Answer 22

In this case, the general formula would be
\(\ln_{e}(y) = x\) is equivalent to \(e^x= y\)

Answer 23

By default if the index isn't given, then it is assumed to be e

Answer 24

In this case, y = (2x + 1), x = 10

Answer 25

Inserting those values into the formula we get:

\(\ln_e(2x+1) = 10\) which becomes \(e^{10} = 2x + 1\) after substitution.

Answer 26

From there, you solve for x to get:

\(\frac{e^{10} - 1}{2} = x\)

Answer 27

ok i get it a little.. can you help me with another one

Answer 28

e^2x - 2e^x -3=0

Answer 29

just one last one

Answer 30

@Hero