Question

What is the sum of the arithmetic sequence 9, 14, 19, , if there are 32 terms?



2,768

2,800

2,832

2,864

Answer 1

a=9
d= 19-14=
=14-9
= 5

finding 32nd term-
a_n=a+(n-1)d
= 9+(31)5
32nd or last term = 164

Now sum of n terms=
S_n = n/2 * (a+l) ,l=last term
therefore, S_32 = 32/2 * (9+164)
= 16 * 173
= 2768

Answer 2

Okay i understand why the end works but i dont understand the beginning specifically d

Answer 3

d is the common difference between any two consecutive no.

Answer 4

so i can use that equation for any problem like that correct?

Answer 5

yes

Answer 6

Wait what does N stand for

Answer 7

n is any no. .