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Chemistry 39 Online
OpenStudy (anonymous):

Which particle among the following will have the smallest de-broglie wavlength, retriceuming that they have the same velocity a) a positron c)an a-particle b) a photon d) a neutron

OpenStudy (dominusscholae):

De Broglie Wavelength = \[h/p, \] h = Planck's constant, p = momentum = mass*velocity. Assuming the velocity is the same, the smallest wavelengths will be for the particles with the GREATEST MASS. Thus, which one here has the greatest mass?

OpenStudy (anonymous):

i too dont know

OpenStudy (dominusscholae):

Hint: An alpha particle has two protons and two neutrons. Photon is massless. Positron is same mass as electron. Electron's mass < Proton's mass.

OpenStudy (anonymous):

but the ans. is given a-particle.

OpenStudy (dominusscholae):

yes, since it consists of two protons and two neutrons, which is heavier than the rest.

OpenStudy (anonymous):

so a-particle has largest de-broglie wavelength among the above??

OpenStudy (dominusscholae):

Yes

OpenStudy (anonymous):

ok thanks

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