Question

Find the average value of function f(x)= x^2-19 from x=0 to x=3.

Answer 1

\[\frac{1}{3}\int_0^3(x^2-9)dx\]

Answer 2

rather
\[\frac{1}{3}\int_0^3(x^2-19)dx\]

Answer 3

should be ok since
\[\frac{1}{3}\int_0^3x^2dx-\frac{1}{3}\int_0^319dx\]
is not too bad
second integral is \(-19\) by your eyeballs
first one is \(\frac{1}{3}\times \frac{3^3}{3}=3^3=27\)

Answer 4

wow that was wrong!!

Answer 5

\[\frac{3^3}{3^2}=3\] or the first one

Answer 6

for a final answer of \(3-19=-16\) i think.