Question

solve for quadratic equ
2x^2 - 4x + 1 = 0

Answer 1

oops nvm

Answer 2

Do you know what a=
b=
and c=

Answer 3

am going to explain to you detailed every exercise of the following way:

First exercise:

2x² - 4x + 1 = 0

I am going to apply the general formula where the values are:

a=2
b =-4
c=1

Chord to the quadratic form ax² + bx+c.

The formula is:

....-b ± √b²-4ac
x=------------------
............2a

Now we replace the values, this way:

....-(-4) ± √(-4)²-4(2)(1)
x=----------------------------
..................2(4)

We solve what is in of the square, like that root:

.....4 ± √16-8
x=----------------
...........8

.....4 ± √8
x=------------
..........8

We rationalize, though really it does not have square exact root and it would remain like that:

....4 ± 2√2
x=------------
..........8

Now we look for both values for both signs independently, of the following way:

And the looked results are:

x1 = 4 + 2√2 / 8
x2= 4 - 2√2 / 8

Second exercise:

3x² + 2x - 7 = 0

I am going to apply the general formula where the values are:

a=3
b =2
c=-7

Chord to the quadratic form ax² + bx+c.

The formula is:

....-b ± √b²-4ac
x=------------------
............2a

Now we replace the values, this way:

....-(2) ± √(2)²-4(3)(-7)
x=----------------------------
................2(-7)

We solve what is in of the square, like that root:

.....-2 ± √4+84
x=----------------
...........-14

.....-2 ± √88
x=------------
........-14

We rationalize, though really it does not have square exact root and it would remain like that:

....-2 ± 2√22
x=--------------
..........-14

Now we look for both values for both signs independently, of the following way:

And the looked results are:

x1 = -2 + 2√22 / -14 = 2 - 2√22 /14
x2= -2 - 2√22 / -14 = 2 + 2√22 / 14

I hope that my explanations you are of usefulness! Greet from Colombia, on happy Friday and bye-bye =).
Source(s):
University student of Civil Engineering
I walk of vacations still
Experience pesonal and without web

Answer 4

quadratic formula for this one

Answer 5

yess

Answer 6

i just need to have it factored but i think its prime

Answer 7

you cannot factor using integers, so you need to use the quadratic formula
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with \(a=2,b=-4,c=1\)

Answer 8

follow @linda18, she has everything I was to lazy to write lol

Answer 9

i amm

Answer 10

make the number replacements and get
\[x=\frac{4\pm\sqrt{(-4)^2-4\times 2\times 4}}{2\times 1}\] then some careful arithmetic
\[x=\frac{4\pm\sqrt{16-8}}{4}=\frac{4\pm\sqrt{8}}{4}\]
\[x=\frac{4\pm2\sqrt{2}}{4}\]
\[x=\frac{2(2\pm\sqrt{2})}{4}=\frac{2\pm\sqrt{2}}{2}\]

Answer 11

so x is\[\sqrt{2}\]

Answer 12

use this formula :
-b ± √b²-4ac
x=------------------
2a
it will help u

Answer 13

yeah pm 1.41

Answer 14

k thanks

Answer 15

welcum =)