PLEASE HELP, easy.
What are the exact solutions of x^2-5x-7=0 ?
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OpenStudy (anonymous):
This does not factor.
OpenStudy (anonymous):
does no factor
OpenStudy (anonymous):
I know, u have to use the quadratic formula
OpenStudy (jiteshmeghwal9):
use formula\[-b \pm \sqrt{b^2-4ac} \over 2a\]
OpenStudy (anonymous):
But I mess up on it I can't do it!!
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OpenStudy (anonymous):
Cool, use the formula then =)
OpenStudy (anonymous):
Alright I'll try :)
OpenStudy (anonymous):
you need to know a,b, and c
a=1
b=5
c=7
Now substitute this into the quadratic formula and solve
OpenStudy (anonymous):
Okay thanks guys
OpenStudy (anonymous):
@aussy123 b=-5 and c=-7
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OpenStudy (anonymous):
Oh they are negative?
OpenStudy (anonymous):
Yes. b and c are negative.
OpenStudy (anonymous):
Thnx
OpenStudy (jiteshmeghwal9):
so,\[5 \pm \sqrt{25+28} \over 2\]after solving these make two roots on as\[\alpha=\frac{-b + \sqrt{b^2-4ac}}{2a}\] & second as\[\beta=\frac{-b -\sqrt{b^2-4ac}}{2a}\]
OpenStudy (anonymous):
@SmartWish Thanks for the correction
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OpenStudy (anonymous):
So wait
OpenStudy (anonymous):
You get 53 over 2
OpenStudy (anonymous):
@aussy123
OpenStudy (anonymous):
Im checking now
OpenStudy (anonymous):
use quasratic equation
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OpenStudy (anonymous):
Oh got it
OpenStudy (anonymous):
use quadratic equation
-b ± √b²-4ac
x=------------------
2a
a=1
b=-5
c=-7
put them in above equation