Question

2x=5+4x
solve by completing the square.

Answer 1

there is no need of completing square it is linear variable can be solved easily
put all x terms on one side and all constants on other side
4x-2x=-5
2x=5
x=5/2

Answer 2

4x-2x=-5
2x=-5
x=-5/2

Answer 3

ERR SORRY I TYPED IT WRONG.

2x=5+4/x
solve by completing the square.

Answer 4

yeahh i agree with sami!

Answer 5

guys?

Answer 6

So 2x^2 = 5x +4 then...

Answer 7

(x not zero obviously)

Answer 8

uhhokay then...
2x^2-5x-4=0 right?

Answer 9

then 2x^2-5x+(5/2)^2=4+(5/2)^2 ?

Answer 10

Might as well leave the 4 on the rhs
2x^2 -5x = 4
And divide by 2 so we get a single x^2
x^2 -5/2 x = 2

Answer 11

So you take half the coefficient of x.....

Answer 12

o.o i have never done that before o.o

Answer 13

so now what do we do?

Answer 14

(x-5/4)^2 - (5/4)^2 = 2 etc...

Answer 15

Just the usual from here....

Answer 16

wait, i'm so confused. x^2-5/2x+(-5/4x)^2=2

Answer 17

It's (x-5/4)^2 - (5/4)^2 = 2 (not what you have put)

Answer 18

how do you get that though?

Answer 19

By putting
(x-5/4)^2 I have added (5/4)^2 to the left side so I have to take it away again to get back to where I started.