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Chemistry 20 Online
OpenStudy (anonymous):

Please help!!! If the formula for a compound is represented by XY2 and the charge on the Y ion is -2, what is the charge in the X ion?

OpenStudy (anonymous):

okk

OpenStudy (anonymous):

if charge on X is a and on Y is b, then formula is XbYa. can u do it now?

OpenStudy (btaylor):

the charge of X must add to the charge of Y2 to make zero. Y2 has a total charge of -4 (2 x -2), so X must be +4 in order to make the compound neutral. XY2 could be something like CO2

OpenStudy (anonymous):

dont get :(

OpenStudy (anonymous):

okk...lets take an example

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

if charge on X is +6 and on Y is -2, then formula is X2Y6 which can be simplified to XY3. So, assume charge on X is a in this case and solve

OpenStudy (anonymous):

if XY2 and the charge on the Y ion is -2 the what represents Y 2 or -2?

OpenStudy (anonymous):

if charge on X is +a and on Y is -2, then formula is X2Ya which can be simplified to X1Ya/2.

OpenStudy (anonymous):

no no noo...XY2 means charge on X might be +2

OpenStudy (anonymous):

!!!!!!! me no get it! :(

OpenStudy (anonymous):

its oki. lets start again.

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

if charge on X is a and on Y is b, then formula is XbYa. Notice, that a and b are interchanged.

OpenStudy (anonymous):

clear?

OpenStudy (anonymous):

you mean when they cross right?

OpenStudy (anonymous):

yepp, and the sign doesnt matter, altho it ll be +a and -b

OpenStudy (anonymous):

so is X2Yb ?

OpenStudy (anonymous):

X2Ya , we assumed a on X

OpenStudy (anonymous):

right they cross so a goes to the Y :) my mistake

OpenStudy (anonymous):

yepp, but we are given XY2

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

thats is X1Y2, and we got to change X2Ya into X1Ya/2 ; as the ratio remains the same, we can do that

OpenStudy (anonymous):

clear?

OpenStudy (anonymous):

so the charge of x is 2?

OpenStudy (anonymous):

nah. a/2 = 2, so a = 4

OpenStudy (anonymous):

oh so the charge of x is four?

OpenStudy (anonymous):

got it?

OpenStudy (anonymous):

Yepp

OpenStudy (anonymous):

nope ?? I dont get the radio part :?

OpenStudy (anonymous):

radio??

OpenStudy (anonymous):

ratio :)

OpenStudy (anonymous):

X2Y4 can be written as XY2, do u get that?

OpenStudy (anonymous):

waaa!;( no how do you get for by multiplication right?

OpenStudy (anonymous):

Nah The ratio of X and Y is 2/4 which can also be written as 1/2. SImple maths! :)

OpenStudy (anonymous):

why 4? :/ O.o?

OpenStudy (anonymous):

Just randomly chose it. Lets take another example. X3Y9 can be written as XY3.

OpenStudy (anonymous):

ramdomly? you can do that?? ok XY3

OpenStudy (anonymous):

lol that was just to explain to you the concept... Clear now?

OpenStudy (anonymous):

oh!!! but XY3 if u simplify is going t be 1. And if its XY4 IS XY2 ?

OpenStudy (anonymous):

Sorry, you lost me

OpenStudy (anonymous):

what am saying is that I you choose a ramdom numeber the there is no a specific final answer..

OpenStudy (anonymous):

No no noo. Use this method: if charge on X is a and on Y is b, then formula is XbYa. Notice, that a and b are interchanged. X2Ya in this case , as we assumed a on X as the ratio remains the same, we can write X2Ya as X1Ya/2 X1Ya/2 is equivalent to X1Y2, implies a/2 = 2 or, a = 4 charge on X is 4

OpenStudy (anonymous):

oh ok I get it..Thank you so much!

OpenStudy (anonymous):

Welcome again! :)

OpenStudy (anonymous):

haha :)

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