Question

5/(12+4x)-7/(9+3x))

Answer 1

\[\frac{5}{(12+4x)}-\frac{7}{(9+3x)}\]

Answer 2

You want to simplify this right?

Answer 3

correct

Answer 4

Great so one of the things we can do is factor out the denominator for both fractions. For example the first denominator we have (12+4x)

In this case we can factor out a 4 like this

4(3+x)

Answer 5

can you do the same to the next fraction and factor it out?

Answer 6

yes it would be 3(3+x)

Answer 7

Great now we have this
\[\frac{5}{4(3+x)}-\frac{7}{3(3+x)}\]or we can rewrite it like this\[\frac{5}{4}\frac{1}{(3+x)}-\frac{7}{3}\frac{1}{(3+x)}\]

Answer 8

in this way we can subtract the outside numbers 5/4 and 7/3 while keeping the 1/(x+3)

To do that we need a common denominator for 5/4 and 7/3

Answer 9

12

Answer 10

great now we have\[\frac{15}{12}\frac{1}{(x+3)}-\frac{28}{12}\frac{1}{(x+3)}\]and we can then simplify it like this\[(\frac{15}{12}-\frac{28}{12})\frac{1}{(x+3)}\]

Answer 11

can you tell me what we get after simplifying further more from the last step that I left.

Answer 12

14/12(x+3)

Answer 13

there is more negative than positive

Answer 14

\[-\frac{14}{12}\frac{1}{(x+3)}\]

Answer 15

final answe?

Answer 16

Sorry made a mistake there.

Answer 17

Yeah