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What is the equation of a circle that passes through point J(6, 4) and has center K (1, -8).
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equation of a circle with radius \(\large r\) and the center \(\large (a,b)\) is \[\large (x-a)^2+(y-b)^2=r^2\]
now u tell me what are the values of a and b?
i got 169 as the answer.
plz show your work
u mean r^2=169 am i right?
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Yes
exactly so r=13
and the equation will be \[\large (x-1)^2+(y+8)^2=169\] am i right?
Exactly
almost done
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