Question

What is the equation of a circle that passes through point J(6, 4) and has center K (1, -8).

Answer 1

equation of a circle with radius \(\large r\) and the center \(\large (a,b)\) is
\[\large (x-a)^2+(y-b)^2=r^2\]

Answer 2

now u tell me what are the values of a and b?

Answer 3

i got 169 as the answer.

Answer 4

plz show your work

Answer 5

u mean r^2=169
am i right?

Answer 6

Yes

Answer 7

exactly
so r=13

Answer 8

and the equation will be
\[\large (x-1)^2+(y+8)^2=169\]
am i right?

Answer 9

Exactly

Answer 10

almost done