Question

Intergral of (x^4/(1+x^6))^2 dx over -1,inf

Answer 1

http://www.wolframalpha.com/input/?i=Intergral+of+%28x^4%2F%281%2Bx^6%29%29^2+dx+over+-1%2Cinf+

Answer 2

Do I read this right?

\[ \large \int_{-1}^\infty \frac{x^8}{(1+x^6)^2} dx\]

Answer 3

Partial fraction decomposition and a lot of spare time (-:

Answer 4

Can u help me I have 12 minutes left on a test

Answer 5

I doubt that this problem can be solved within 12 minutes, except there is some fundamental trick I am missing here or I am unable to see, anyone any ideas?

Answer 6

if the denominator was something in the form x^5, it would be possible, but it's not.

Answer 7

except you copied the problem wrong, this one is pretty hairy.

Answer 8

if the numerator*

Answer 9

Ok what about this one.....

Answer 10

Integral of 1/(4 sqrt(1+x)) dx over 0,inf

Answer 11

\[ \large \frac{1}{4} \int_0^\infty (1+x)^{-\frac{1}{2}}dx \]

Answer 12

Continue

Answer 13

6minutes left

Answer 14

oops sorry. well then integrate it.

Answer 15

\[ \large \frac{1}{2} \sqrt{1+x} \]

Answer 16

and this integral does not converge obviously, hence there is no limit.

Answer 17

and that's your answer.

Answer 18

U can continue I have extra time

Answer 19

if you want.

Answer 20

Yes plz

Answer 21

But this problem is already finished, there isn't anything more to add.

Answer 22

Thank u

Answer 23

\[ \large \left. \frac{1}{2}\sqrt{1+x} \right|_0^\infty \] = does not converge, there is no solution.