Question

how do you solve this problem? n^3/4 =4n

Answer 1

Multiply it out, get it all on one side and factor

Answer 2

\[n^3\div4=4n\] try to get the n on one side

Answer 3

could please show me the method? I need to see the steps to learn. Thank you.

Answer 4

n^3/4 =4n ->
n^3 = 16n ->
n^3 - 16n = 0


OK so far?

Answer 5

yes. Thank you.

Answer 6

n^3 - 16n = 0 ->

n(n^2-16)=0

Can you do it now?

Answer 7

The next step please?

Answer 8

n(n^2-16)=0 ->
n(n+4)(n-4) = 0

Answer 9

is it n=-4 and n= 4

Answer 10

It is a cubic equation, 3 roots...

Answer 11

how do I get the last root please?

Answer 12

We have n(n+4)(n-4) = 0 (3 things multiplied together to get 0)
Maybe if I write (n+0)(n+4)(n-4) = 0 it is clearer?

Answer 13

You got it now, right?

Answer 14

yes, it's n=0 n=-4 n=4 right?

Answer 15

That's right.

Answer 16

Thank you so much. I appreciate it.

Answer 17

ur welcome.