Ask your own question, for FREE!
Chemistry 10 Online
OpenStudy (anonymous):

The compound nickel (III) chloride dihydrate has ____ mole(s) of water for every ____ mole(s) of ionic compound. three, two two, three one, two two, one

OpenStudy (anonymous):

Am guessing is c

OpenStudy (anonymous):

Are you sure??

OpenStudy (anonymous):

nope :)

OpenStudy (anonymous):

I mean are you sure in guessing??

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

Do you know the formula for Nickel(III) chloride dihydrate??

OpenStudy (anonymous):

The formula for Nickel(III) Chloride dihydrate is given by: \[\large \color{green}{NiCl_3.2H_2O}\]

OpenStudy (anonymous):

Getting @Nana3456

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

oh so am right for every one mole NiCl3 there are 2 two H2O molecules :)

OpenStudy (anonymous):

But answer is not C..

OpenStudy (anonymous):

??

OpenStudy (anonymous):

dont get it then :/

OpenStudy (anonymous):

I actually think is NiCl2 * 2H2O

OpenStudy (anonymous):

See, Here Ionic compound is \(NiCl_3\) So, 1 mole of Organic Compound gives you two moles of Water.. As in question water moles are coming first and then the moles of Ionic compound are coming so, two, one will be the answer..

OpenStudy (anonymous):

No, in bracket there is written (III) and not (II)..

OpenStudy (anonymous):

oh O.O!

OpenStudy (anonymous):

Getting?? Read the question carefully..

OpenStudy (anonymous):

YES

OpenStudy (anonymous):

Got the answer for this?? First blank is for water moles that are 2.. Second blank is for ionic compound that is \(NiCl_3\) in this case.. So, 1..

OpenStudy (anonymous):

yeah I get it now thank you so much! :) :) :)

OpenStudy (anonymous):

Welcome dear..

OpenStudy (anonymous):

:)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!