Question

the integral of ((e^x +1)^(-1/2))e^x dx from ln8 to ln 24

Answer 1

\[
u= 1 + e^x
\]

Answer 2

du = e^x dx

Answer 3

\[
\int ((e^x +1)^{-1/2})e^x dx=\int u^{-1/2} du
\]

Answer 4

Do you know how to finish it from here

Answer 5

No, are the limits still ln8 to ln24 or do they change

Answer 6

Get the integral in terms of u, replace u by its value and keep the same limits

Answer 7

Or you can change the limit before the integration.

Answer 8

So is the final answer going to be 4?

Answer 9

Yes

Answer 10

Thanks